Introduction to Moles

January 25, 2011

We began class by stamping our homework, the Mole Lab, and reviewing pages 7 and 8.
(Review)
- a compound is ionic if it contains a metal such as NaNO3, and is simply named sodium nitrate
- if the metal is a transition metal, the compound includes roman numerals, such as Fe3N2, which is named iron (II) nitride
- a compound is covalent if it contains two nonmetals such as PCl5, which includes a prefix, in this case, phosphorus pentachloride

- to calculate the molar mass of a compound, first write the compound's formula. Then take the number of atoms of the first element and multiply it by the element's atomic mass, found on the periodic table. Continue to do this with each element, and add up the masses of each element at the end. For example,
carbon dioxide --- CO2
(one carbon atom, 1 x 12.01 (the atomic mass of carbon)) + (2 x 16.00) = 44.01 g
44.01 g is the molar mass of carbon dioxide (for each mole of CO2 there is 44.01 g)

To calculate the number of moles of 50g of carbon dioxide, use the multiplication method that I can't remember the name of. It involves canceling out units of measurement by putting them diagonally across from eachother ------ x ------- (< like that)

SO...
begin the equation with 50 g of CO2.
50g x 1 mole/44.01 g --- grams cancel out, so you are left to divide 50 by 44.01, to get the answer 1.14 mol CO2

Pages 1 and 2 just went into more depth with the multiplication method with the name I can't remember.
Here's an example problem: What is the mass of 3.57 x 10^-4 mol of N2O5?
start off with what the problem gives you-
3.57 x 10 ^-4 mol N2O5 x 108.02* g/ 1 mol -- mol cancels out, leaving you to multiply 3.57 x 10^-4 by 108.0 to get .0386 g N2O5 (you might want to round that)

*you get 108.02 (the molar mass of N2O5) by (2 x 14.01) + (5 x 16.00)

Thats basically it. The homework was to finish pages 1 and 2.